Решите уравнение: 64x-48x^2+9x^3=0.

\[64x - 48x^{2} + 9x^{3} = 0\]

\[x\left( 9x^{2} - 48x + 64 \right) = 0\]

\[x(3x - 8)^{2} = 0\]

\[x = 0;\ \ \]

\[3x = 8\]

\[x = \frac{8}{3} = 2\frac{2}{3}.\]

\[Ответ:x = 0;\ x = 2\frac{2}{3}.\]