Решите уравнение: (3x-1)/4-(4x+1)/3=7/12.

\[\frac{3x - 1}{4} - \frac{4x + 1}{3} = \frac{7}{12}\text{\ \ \ \ \ }| \cdot 12\]

\[3 \cdot (3x - 1) - 4 \cdot (4x + 1) = 7\]

\[9x - 3 - 16x - 4 = 7\]

\[- 7x = 7 + 7\]

\[- 7x = 14\]

\[x = - 2\]

\[Ответ:x = - 2.\]