Решите уравнение: 3x^2-4x-4=0.

\[3x^{2} - 4x - 4 = 0\]

\[D = 16 + 48 = 64\]

\[x_{1} = \frac{4 + 8}{6} = \frac{12}{6} = 2;\ \ \ \ \ \ \]

\[x_{2} = \frac{4 - 8}{6} = - \frac{4}{6} = - \frac{2}{3}.\]

\[Ответ:x = - \frac{2}{3};\ \ x = 2.\]