Решите уравнение: 25x-x^-1=0.

\[25x - x^{- 1} = 0\]

\[25x^{\backslash x} - \frac{1}{x} = 0;\ \ \ x \neq 0\]

\[25x^{2} - 1 = 0\]

\[25x^{2} = 1\]

\[x^{2} = \frac{1}{25}\]

\[x = \pm \frac{1}{5}\]

\[x = \pm 0,2.\]