Решите уравнение: 2005x^2+2006x+1=0.

\[2005x^{2} + 2006x + 1 = 0\]

\[D = 2006^{2} - 4 \cdot 2005 \cdot 1 =\]

\[= 4\ 024\ 036 - 8020 =\]

\[= 4\ 016\ 016\]

\[\sqrt{D} = \sqrt{4016016} = 2004\]

\[x_{1} = \frac{- 2006 + 2004}{2 \cdot 2005} = \frac{- 2}{4010} =\]

\[= - \frac{1}{2005}\]

\[x_{2} = \frac{- 2006 - 2004}{2 \cdot 2005} = \frac{- 4010}{4010} =\]

\[= - 1\]

\[Ответ:\ - \frac{1}{2005};\ - 1.\]