Решите уравнение: 35x^2-12x+1=0.

\[35x^{2} - 12x + 1 = 0\]

\[D = ( - 12)^{2} - 4 \cdot 35 \cdot 1 =\]

\[= 144 - 140 = 4;\ \ \ \ \sqrt{D} = 2.\]

\[x_{1} = \frac{12 + 2}{2 \cdot 35} = \frac{14}{70} = \frac{1}{5};\ \ \ \ \ \ \]

\[\ x_{2} = \frac{12 - 2}{2 \cdot 35} = \frac{10}{70} = \frac{1}{7}\]

\[Ответ:\ \ \ \frac{1}{5};\ \frac{1}{7}\text{\ .}\]