Решите уравнение: |2x-y-3|+(x+3y-5)^2=0.

\[|2x - y - 3| + (x + 3y - 5)^{2} = 0\]

\[\left\{ \begin{matrix} 2x - y - 3 = 0\ \ \ \ \ \ \ \ \ \ \ \\ x + 3y - 5 = 0\ \ \ | \cdot 2 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 2x - y - 3 = 0\ \ \ \ \ \\ 2x + 6y - 10 = 0 \\ \end{matrix} - \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - 7y = - 7 \\ x = \frac{3 + y}{2} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 1 \\ x = 2 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} y - 2x + 3 = 0\ \ \ | \cdot 3 \\ x + 3y - 5 = 0\ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 3y - 6x = - 9 \\ 3y + x = 5 \\ \end{matrix} - \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - 7x = - 14 \\ y = \frac{5 - x}{3} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} x = 2 \\ y = 1 \\ \end{matrix} \right.\ \]

\[Ответ:(2;1)\text{.\ }\]