Решите систему уравнений: (3x-2y)/3-(4x+5)/4=(7x-10)/8, (6x-5y)/2+(2x+y)/5=x+2y.

\[\left\{ \begin{matrix} - 16y - 21x = 0\ \ \ | \cdot 8 \\ 24x - 43y = 0\ \ \ \ \ \ | \cdot 7 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - 168x - 128y = 0 \\ 168x - 301y = 0\ \ \ \\ \end{matrix} + \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - 429y = 0 \\ x = 0\ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 0 \\ x = 0 \\ \end{matrix} \right.\ \]

\[Ответ:(0;0)\text{.\ \ }\]