Решите систему уравнений: (x+2)/6-(y-3)/4=1, (x-2)/4-(y-4)/2=1.

\[\left\{ \begin{matrix} \frac{x + 2}{6} - \frac{y - 3}{4} = 1\ \ \ | \cdot 12 \\ \frac{x - 2}{4} - \frac{y - 4}{2} = 1\ \ \ \ \ | \cdot 4 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 2x + 4 - 3y + 9 = 12 \\ x - 2 - 2y + 8 = 4\ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\ \left\{ \begin{matrix} 2x - 3y = - 1\ \ \ \ \ \ \ \ \ \\ x - 2y = - 2\ \ \ \ | \cdot 2 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 2x - 3y = - 1 \\ 2x - 4y = - 4 \\ \end{matrix} - \right.\ \]

\[\ \left\{ \begin{matrix} y = 3\ \ \ \ \ \ \ \ \ \ \ \ \ \\ x = \frac{- 2 + 2y}{1} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 3 \\ x = 4 \\ \end{matrix} \right.\ \]

\[Ответ:(4;3).\]