Решите систему неравенств: 7x-3<0; 14/(16x^2-9)<0.

\[\left\{ \begin{matrix} 7x - 3 < 0\ \ \ \ \\ \frac{14}{16x^{2} - 9} < 0 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} x < \frac{3}{7}\text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \\ 16x^{2} - 9 < 0 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} x < \frac{3}{7}\text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \\ (4x - 3)(4x + 3) < 0 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} x < \frac{3}{7}\text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \\ 16 \cdot \left( x - \frac{3}{4} \right)\left( x + \frac{3}{4} \right) < 0 \\ \end{matrix} \right.\ \]

\[Ответ:\left( - 0,75;\frac{3}{7} \right).\]