Решите неравенство: (x^2+3x-18)^2<(x^2+x-12)^2.

\[(2x - 6)\left( 2x^{2} + 4x - 30 \right) < 0\]

\[4 \cdot (x - 3)\left( x^{2} + 2x - 15 \right) < 0\]

\[4 \cdot (x - 3)(x - 3)(x + 5) < 0\]

\[4 \cdot (x - 3)^{2}(x + 5) < 0\]

\[Ответ:( - \infty; - 5).\]