Вопрос:

Решите неравенство: ((x+4)/(x+3))^2+((x-4)/(x-3))^2>(2x^2-32)/(x^2-9).

Ответ:

\[\left( \frac{x + 4}{x + 3} \right)^{2} + \left( \frac{x - 4}{x - 3} \right)^{2} > \frac{2x^{2} - 32}{x^{2} - 9}\]

\[\left( \frac{x + 4^{\backslash x - 3}}{x + 3} - \frac{x - 4^{\backslash x + 3}}{x - 3} \right)^{2} > 0\]

\[\left( \frac{2x}{(x + 3)(x - 3)} \right)^{2} > 0\]

\[\frac{4x^{2}}{(x + 3)^{2}(x - {3)}^{2}} > 0\]

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