Решите неравенство: (4x-6)^2>=(6x-4)^2.

\[(4x - 6)^{2} \geq (6x - 4)^{2}\]

\[16x^{2} - 48x + 36 \geq 36x^{2} - 48x + 16\]

\[- 20x^{2} \geq - 20\]

\[20x^{2} \leq 20\]

\[x^{2} \leq 1\]

\[- 1 \leq x \leq 1.\]

\[Ответ:\ - 1 \leq x \leq 1.\]