Решите неравенство: x^2+2x-15<=0.

\[x^{2} + 2x - 15 \leq 0\]

\[D_{1} = 1 + 15 = 16\]

\[x_{1} = - 1 + 4 = 3;\]

\[x_{2} = - 1 - 4 = - 5.\]

\[(x + 5)(x - 3) \leq 0\]

\[- 5 \leq x \leq 3.\]

\[Ответ:\ - 5 \leq x \leq 3.\]