Решите неравенство: 4/(3x+1)^2-8/(3x+1)+3<=0.

\[\frac{- 24x - 4 + 27x^{2} + 18x + 3}{(3x + 1)^{2}} \leq 0\]

\[\frac{27x^{2} - 6x - 1}{(3x + 1)^{2}} \leq 0\]

\[\frac{27 \cdot \left( x - \frac{1}{3} \right)\left( x + \frac{1}{9} \right)}{9 \cdot \left( x + \frac{1}{3} \right)^{2}} \leq 0\]

\[Ответ:\left\lbrack - \frac{1}{9};\ \frac{1}{3} \right\rbrack.\]