\[y = kx + b;\ \ A\ ( - 2;1);\ \ B\ (3;4):\]
\[\left\{ \begin{matrix} - 2k + b = 1 \\ 3k + b = 4 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ }\]
\[\left\{ \begin{matrix} - 5k = - 3\ \\ b = 1 + 2k \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ }\]
\[\left\{ \begin{matrix} k = \frac{3}{5} = 0,6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ b = 1 + \frac{6}{5} = 2\frac{1}{5} = 2,2 \\ \end{matrix} \right.\ \]
\[Уравнение\ данной\ прямой:\]
\[y = 0,6x + 2,2.\]