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Вопрос:

Приведите к общему знаменателю дроби: a) \(\frac{1}{6}\) и \(\frac{1}{4}\); б) \(\frac{7}{9}\) и \(\frac{7}{12}\); г) \(\frac{7}{18}\) и \(\frac{10}{27}\); д) \(\frac{3}{10}\) и \(\frac{3}{14}\); ж) \(\frac{13}{24}\) и \(\frac{8}{36}\); к) \(\frac{7}{10}\) и \(\frac{777}{1000}\); з) \(\frac{11}{30}\) и \(\frac{7}{45}\); л) \(\frac{43}{2500}\) и \(\frac{411}{7500}\).

Ответ:

a) \(\frac{1}{6}\) и \(\frac{1}{4}\). НОЗ (6,4) = 12. \(\frac{1}{6} = \frac{1 \cdot 2}{6 \cdot 2} = \frac{2}{12}\) \(\frac{1}{4} = \frac{1 \cdot 3}{4 \cdot 3} = \frac{3}{12}\) б) \(\frac{7}{9}\) и \(\frac{7}{12}\). НОЗ (9,12) = 36. \(\frac{7}{9} = \frac{7 \cdot 4}{9 \cdot 4} = \frac{28}{36}\) \(\frac{7}{12} = \frac{7 \cdot 3}{12 \cdot 3} = \frac{21}{36}\) г) \(\frac{7}{18}\) и \(\frac{10}{27}\). НОЗ (18,27) = 54. \(\frac{7}{18} = \frac{7 \cdot 3}{18 \cdot 3} = \frac{21}{54}\) \(\frac{10}{27} = \frac{10 \cdot 2}{27 \cdot 2} = \frac{20}{54}\) д) \(\frac{3}{10}\) и \(\frac{3}{14}\). НОЗ (10,14) = 70. \(\frac{3}{10} = \frac{3 \cdot 7}{10 \cdot 7} = \frac{21}{70}\) \(\frac{3}{14} = \frac{3 \cdot 5}{14 \cdot 5} = \frac{15}{70}\) ж) \(\frac{13}{24}\) и \(\frac{8}{36}\). НОЗ (24,36) = 72. \(\frac{13}{24} = \frac{13 \cdot 3}{24 \cdot 3} = \frac{39}{72}\) \(\frac{8}{36} = \frac{8 \cdot 2}{36 \cdot 2} = \frac{16}{72}\) к) \(\frac{7}{10}\) и \(\frac{777}{1000}\). НОЗ (10,1000) = 1000. \(\frac{7}{10} = \frac{7 \cdot 100}{10 \cdot 100} = \frac{700}{1000}\) \(\frac{777}{1000} = \frac{777}{1000}\) з) \(\frac{11}{30}\) и \(\frac{7}{45}\). НОЗ (30,45) = 90. \(\frac{11}{30} = \frac{11 \cdot 3}{30 \cdot 3} = \frac{33}{90}\) \(\frac{7}{45} = \frac{7 \cdot 2}{45 \cdot 2} = \frac{14}{90}\) л) \(\frac{43}{2500}\) и \(\frac{411}{7500}\). НОЗ (2500, 7500) = 7500. \(\frac{43}{2500} = \frac{43 \cdot 3}{2500 \cdot 3} = \frac{129}{7500}\) \(\frac{411}{7500} = \frac{411}{7500}\)

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