Найдите производную функции: 10) y=\frac{x-2}{2x+4}

10) $y = \frac{x - 2}{2x + 4}$ $y' = \frac{(x - 2)'(2x + 4) - (x - 2)(2x + 4)'}{(2x + 4)^2} = \frac{(1)(2x + 4) - (x - 2)(2)}{(2x + 4)^2} = \frac{2x + 4 - 2x + 4}{(2x + 4)^2} = \frac{8}{(2x + 4)^2} = \frac{8}{4(x + 2)^2} = \frac{2}{(x + 2)^2}$ Ответ: $y' = \frac{2}{(x + 2)^2}$