\[x^{2} + bx + c = 0\]
\[- \frac{1}{3}\ и\ \ 4\]
\[x_{1} + x_{2} = - \frac{1}{3} + \frac{1}{4} = \frac{- 4 + 3}{12} =\]
\[= - \frac{1}{12} = - b \Longrightarrow b = \frac{1}{12}.\]
\[x_{1} \cdot x_{2} = - \frac{1}{3} \cdot \frac{1}{4} =\]
\[= - \frac{1}{12} \Longrightarrow c = - \frac{1}{12}.\]
\[Ответ:b = \frac{1}{12};\ \ c = - \frac{1}{12}.\]