651. Найдите корень уравнения: a) (6x-5)/7 = (2x-1)/3 + 2; б) (5-x)/2 + (3x-1)/5 = 4; г) (4y-11)/15 + (13-7y)/20 = 2; д) (5-6y)/3 + y/8 = 0;

a) \(\frac{6x-5}{7} = \frac{2x-1}{3} + 2\) \(\frac{6x-5}{7} = \frac{2x-1+6}{3}\) \(\frac{6x-5}{7} = \frac{2x+5}{3}\) \(3(6x-5) = 7(2x+5)\) \(18x - 15 = 14x + 35\) \(18x - 14x = 35 + 15\) \(4x = 50\) \(x = \frac{50}{4} = \frac{25}{2}\) Ответ: \(x = \frac{25}{2}\) б) \(\frac{5-x}{2} + \frac{3x-1}{5} = 4\) \(\frac{5(5-x) + 2(3x-1)}{10} = 4\) \(25 - 5x + 6x - 2 = 40\) \(x + 23 = 40\) \(x = 17\) Ответ: \(x = 17\) г) \(\frac{4y-11}{15} + \frac{13-7y}{20} = 2\) \(\frac{4(4y-11) + 3(13-7y)}{60} = 2\) \(16y - 44 + 39 - 21y = 120\) \(-5y - 5 = 120\) \(-5y = 125\) \(y = -25\) Ответ: \(y = -25\) д) \(\frac{5-6y}{3} + \frac{y}{8} = 0\) \(\frac{8(5-6y) + 3y}{24} = 0\) \(40 - 48y + 3y = 0\) \(40 - 45y = 0\) \(45y = 40\) \(y = \frac{40}{45} = \frac{8}{9}\) Ответ: \(y = \frac{8}{9}\)