Решебник по математике 6 класс Виленкин ФГОС Часть 1, 2 Часть 2. Задачи на повторение 107

\[\boxed{\mathbf{П.\ 107}}\]

\[2\frac{18}{23} \cdot 1\frac{11}{12} = \frac{64}{23} \cdot \frac{23}{12} = \frac{16}{3} = 5\frac{1}{3}\]

\[2\frac{1}{8} \cdot \frac{4}{17} = \frac{17}{8} \cdot \frac{4}{17} = \frac{1}{2}\]

\[7 - 5\frac{1}{3} + \frac{1}{2} = 1\frac{2}{3} + \frac{1}{2} =\]

\[= 1\frac{4}{6} + \frac{3}{6} = 1\frac{7}{6} = 2\frac{1}{6}\]

\[2\frac{1}{6}\ :1,5 = \frac{13}{6}\ :\frac{3}{2} = \frac{13}{6} \cdot \frac{2}{3} =\]

\[= \frac{13}{9} = 1\frac{4}{9}\]

\[1\frac{4}{9} - \frac{4}{5} = \frac{13}{9} - \frac{4}{5} = \frac{65}{45} - \frac{36}{45} =\]

\[= \frac{29}{45}\]

\[= 2 - \frac{3}{4} = 1\frac{1}{4}\]

\[22\frac{1}{2} \cdot \frac{1}{30} = \frac{45}{2} \cdot \frac{1}{30} = \frac{3}{4}\]

\[\frac{3}{4} - \frac{3}{5} = \frac{15}{20} - \frac{12}{20} = \frac{3}{20}\]

\[\frac{3}{32} \cdot 3\frac{1}{5}\ :\frac{3}{20} = \frac{3}{32} \cdot \frac{16}{5} \cdot \frac{20}{3} =\]

\[= \frac{4}{2} = 2\]

\[5\frac{1}{2}\ :7\frac{1}{3} = \frac{11}{2}\ :\frac{22}{3} = \frac{11}{2} \cdot \frac{3}{22} =\]

\[= \frac{3}{4}\]