Решебник по математике 6 класс Виленкин ФГОС Часть 1, 2 Часть 1. П. 3. Отношения и пропорции Задание 184

\[\boxed{\mathbf{3.184}}\]

\[1)\ \frac{5^{\backslash 5}}{14}\ t + \frac{9^{\backslash 2}}{35}t - \frac{3^{\backslash 10}}{7}t =\]

\[= \frac{25}{70}t + \frac{18}{70}t - \frac{30}{70}t = \frac{13}{70}t\]

\[t = 1\frac{7}{23} = \frac{30}{23}:\]

\[\frac{13}{70} \cdot \frac{30}{23} = \frac{13 \cdot 3}{7 \cdot 23} = \frac{39}{161}.\]

\[2)\ \frac{7^{\backslash 15}}{12}z - \frac{5^{\backslash 10}}{18}z + \frac{13^{\backslash 3}}{60}z =\]

\[= \frac{105}{180}z - \frac{50}{180}z + \frac{39}{180}z =\]

\[= \frac{94}{180}z = \frac{47}{90}z\]

\[z = 3\frac{9}{47} = \frac{150}{47}:\]

\[\frac{47}{90} \cdot \frac{150}{47} = \frac{47 \cdot 15}{9 \cdot 47} = \frac{5}{3} = 1\frac{2}{3}.\]