Решебник по математике 6 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 2 | Страница 29

\[Стр.\ 29.\]

\[\boxed{\mathbf{4.}}\]

\[14 + ( - 14) = 0\]

\[- \frac{2}{3} + \frac{2}{3} = 0\]

\[- 0,8 + 0 = - 0,8\]

\[0 + ( - 10,15) = - 10,15\]

\[7\frac{1}{8} + \left( - 7\frac{1}{8} \right) = 0\]

\[0 + ( - 8) = - 8\]

\[- 9\frac{1}{2} + 9,5 = 0\]

\[10,25 + \left( - 10\frac{1}{4} \right) = 0\]

\[- 57 + 0 = - 57\]

\[\boxed{\mathbf{5.}}\]

\[\boxed{\mathbf{6.}}\]

\[\textbf{а)}\ | - 7| \cdot \left| \frac{1}{7} \right| = 7 \cdot \frac{1}{7} = 1\]

\[| - 7|\ :\left| \frac{1}{7} \right| = 7\ :\frac{1}{7} = 7 \cdot 7 = 49\]

\[\textbf{б)}\ | - 10| + | - 6| = 10 + 6 = 16\]

\[| - 3,7| + | - 1,8| = 3,7 + 1,8 =\]

\[= 5,5\ \]

\[\textbf{в)}\ | - 7| + \left| \frac{1}{7} \right| = 7 + \frac{1}{7} = 7\frac{1}{7}\]

\[| - 7| - \left| \frac{1}{7} \right| = 7 - \frac{1}{7} = 6\frac{6}{7}\ \]

\[\mathbf{г)\ }\left| - \frac{1}{4} \right| + \left| - \frac{3}{8} \right| = \frac{1}{4} + \frac{3}{8} =\]

\[= \frac{2 + 3}{8} = \frac{5}{8}\ \]

\[\left| - \frac{3}{5} \right| + \left| - \frac{1}{5} \right| = \frac{3}{5} + \frac{1}{5} = \frac{4}{5}\]

\[\boxed{\mathbf{7.}}\]

\[\textbf{а)} - 2 \leq x \leq 4:\]

\[x = - 2,\ - 1,\ 0,\ 1,\ 2,\ 3,\ 4.\]

\[\textbf{б)} - 7 \leq x < - 5\]

\[x = - 7,\ - 6.\]

\[\textbf{в)} - 6,2 \leq y < 3:\]

\[y = - 6,\ - 5,\ - 4,\ - 3,\ - 2,\ - 1,\ 0,\ \]

\[1,\ 2.\]

\[\textbf{г)} - 8,3 < z \leq 5:\]

\[z = - 8,\ - 7,\ - 6,\ - 5,\ - 4,\ - 3,\ - 2,\ \]

\[- 1,\ 0,\ 1,\ 2,\ 3,\ 4,\ 5.\ \]