Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 3. Отношения и пропорции Задание 146

\[\boxed{\mathbf{3.146}}\]

\[1)\ 2\frac{1}{4} \cdot 2^{3} = \frac{9}{4} \cdot 8 = 9 \cdot 2 = 18\]

\[2)\ 3\frac{1}{5}\ :2^{4} = \frac{16}{5}\ :16 = \frac{16}{5} \cdot \frac{1}{16} =\]

\[= \frac{1}{5}\]

\[3)\ 4,42 + (2,5)^{3} =\]

\[= 4,42 + 15,625 = 20,045\]

\[4)\ 30 - (3,6)^{2} = 30 - 12,96 =\]

\[= 17,04\]

\[5)\ 3^{3} \cdot \left( 1\frac{1}{3} \right)^{2} = 27 \cdot \left( \frac{4}{3} \right)^{2} =\]

\[= 27 \cdot \frac{16}{9} = 3 \cdot 16 = 48\]

\[6)\ \left( 3\frac{3}{4} \right)^{2}\ :\left( 1\frac{1}{4} \right)^{3} =\]

\[= \left( \frac{15}{4} \right)^{2}\ :\left( \frac{5}{4} \right)^{3} = \frac{225}{16}\ :\frac{125}{64} =\]

\[= \frac{225 \cdot 64}{16 \cdot 125} = \frac{9 \cdot 4}{5} = \frac{36}{5} = \frac{72}{10} =\]

\[= 7,2\]