Решебник по математике 6 класс Мерзляк ФГОС Задание 337

\[\boxed{\mathbf{337\ (337).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[\boxed{\mathbf{337}\mathbf{.}}\]

\[1)\ \frac{31}{58} - \frac{16}{58} = \frac{31 - 16}{58} = \frac{15}{58}\]

\[2)\ \frac{19}{25} + \frac{4}{25} - \frac{22}{25} =\]

\[= \frac{19 + 4 - 22}{25} = \frac{1}{25}\]

\[3)\ \frac{1^{\backslash 5}}{6} + \frac{7^{\backslash 2}}{15} = \frac{5 + 14}{30} = \frac{19}{30}\]

\[4)\ \frac{5^{\backslash 2}}{14} - \frac{1^{\backslash 7}}{4} = \frac{10 - 7}{28} = \frac{3}{28}\]

\[5)\ \frac{3^{\backslash 9}}{4} - \frac{5^{\backslash 3}}{12} + \frac{5^{\backslash 4}}{9} =\]

\[= \frac{27 - 15 + 20}{36} = \frac{32}{36} = \frac{8}{9}\]

\[6)\ 2\frac{3^{\backslash 3}}{8} + 4\frac{5^{\backslash 2}}{12} = 2\frac{9}{24} + 4\frac{10}{24} =\]

\[= 6\frac{19}{24}\]

\[7)\ 3\frac{5^{\backslash 2}}{6} - 1\frac{7}{12} = 3\frac{10}{12} - 1\frac{7}{12} =\]

\[= 2\frac{3}{12} = 2\frac{1}{4}\]

\[8)\ 9\frac{2}{15} - 6\frac{3^{\backslash 3}}{5} = 9\frac{2}{15} - 6\frac{9}{15} =\]

\[= 8\frac{17}{15} - 6\frac{9}{15} = 2\frac{8}{15}\]

\[9)\ 5\frac{7^{\backslash 2}}{18} - 4\frac{11^{\backslash 3}}{12} =\]

\[= 5\frac{14}{36} - 4\frac{33}{36} = 4\frac{50}{36} - 4\frac{33}{36} =\]

\[= \frac{17}{36}\]