Решебник по математике 6 класс Мерзляк ФГОС Задание 336

\[\boxed{\mathbf{336\ (336).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{6}{11} \cdot \frac{4}{7} = \frac{6 \cdot 4}{11 \cdot 7} = \frac{24}{77}\]

\[\boxed{\mathbf{336}\mathbf{.}}\]

\[1)\ \frac{7}{18} + \frac{5}{18} = \frac{7 + 5}{18} = \frac{12}{18} = \frac{2}{3}\]

\[2)\ \frac{29}{64} - \frac{14}{64} - \frac{9}{64} =\]

\[= \frac{29 - 14 - 9}{64} = \frac{6}{64} = \frac{3}{32}\]

\[3)\ \frac{3}{28} + \frac{5^{\backslash 2}}{14} = \frac{3 + 10}{28} = \frac{13}{28}\]

\[4)\ \frac{9^{\backslash 5}}{11} - \frac{2^{\backslash 11}}{5} = \frac{45 - 22}{55} = \frac{23}{55}\]

\[5)\ \frac{9^{\backslash 3}}{16} + \frac{7^{\backslash 2}}{24} - \frac{3^{\backslash 6}}{8} =\]

\[= \frac{27 + 14 - 18}{48} = \frac{23}{48}\]

\[6)\ 1\frac{1^{\backslash 3}}{7} + 2\frac{1^{\backslash 7}}{3} = 3 + \frac{3 + 7}{21} =\]

\[= 3 + \frac{10}{21} = 3\frac{10}{21}\]

\[7)\ 7 - 3\frac{9}{16} = 6\frac{16}{16} - 3\frac{9}{16} = 3\frac{7}{16}\]

\[8)\ 4\frac{7^{\backslash 2}}{33} - 2\frac{3^{\backslash 3}}{22} = 2 + \frac{14 - 9}{66} =\]

\[= 2 + \frac{5}{66} = 2\frac{5}{66}\]

\[9)\ 6\frac{1}{6} - 2\frac{2^{\backslash 2}}{3} = 5\frac{7}{6} - 2\frac{4}{6} =\]

\[= 3 + \frac{7 - 4}{6} = 3\frac{3}{6} = 3\frac{1}{2}\]