Решебник по математике 6 класс Мерзляк ФГОС Задание 311

 

\[\boxed{\mathbf{311\ (312).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \left( 12\frac{19}{24} + 5\frac{19}{28} \right) - 3\frac{19}{24} =\]

\[= \left( 12\frac{19}{24} - 3\frac{19}{24} \right) + 5\frac{19}{28} =\]

\[= 9 + 5\frac{19}{28} = 14\frac{19}{28}\]

\[2)\ 6\frac{4}{9} - \left( 1\frac{7}{24} + 4\frac{4}{9} \right) =\]

\[= \left( 6\frac{4}{9} - 4\frac{4}{9} \right) - 1\frac{7}{24} =\]

\[= 2 - 1\frac{7}{24} = 1\frac{24}{24} - 1\frac{7}{24} = \frac{17}{24}\]

\[\boxed{\mathbf{311\ (}\mathbf{с}\mathbf{).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \left( 9\frac{3}{7} + 2\frac{9}{16} \right) - 5\frac{3}{7} =\]

\[= \left( 9\frac{3}{7} - 5\frac{3}{7} \right) + 2\frac{9}{16} =\]

\[= 4 + 2\frac{9}{16} = 6\frac{9}{16}\]

\[2)\ \left( 4\frac{5}{8} + 1\frac{6}{11} \right) - \frac{6}{11} =\]

\[= \left( 1\frac{6}{11} - \frac{6}{11} \right) + 4\frac{5}{8} = 1 + 4\frac{5}{8} =\]

\[= 5\frac{5}{8}\]

\[3)\ 10\frac{5}{14} - \left( 3\frac{5}{14} + 2\frac{9}{34} \right) =\]

\[= \left( 10\frac{5}{14} - 3\frac{5}{14} \right) - 2\frac{9}{34} =\]

\[= 7 - 2\frac{9}{34} =\]

\[= 6\frac{34}{34} - 2\frac{9}{34} = 4\frac{25}{34}\]

\[4)\ 7\frac{1}{7} - \left( 2\frac{6}{13} + 3\frac{1}{7} \right) =\]

\[= \left( 7\frac{1}{7} - 3\frac{1}{7} \right) - 2\frac{6}{13} =\]

\[= 4 - 2\frac{6}{13} =\]

\[= 3\frac{13}{13} - 2\frac{6}{13} = 1\frac{7}{13}\]

\[\boxed{\mathbf{311}\mathbf{.}}\]

\[1)\ \frac{4}{9};\]

\[2)\ \frac{8}{13};\]

\[3)\ \frac{35}{44};\]

\[4)\ \frac{16}{71};\]

\[5)\ \frac{92}{123}.\]