Решебник по математике 6 класс Мерзляк ФГОС Задание 280

 

\[\boxed{\mathbf{280\ (281)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 4\frac{3}{16} - \frac{5^{\backslash 2}}{8} = 3\frac{19}{16} - \frac{10}{16} =\]

\[= 3\frac{9}{16}\]

\[2)\ 6\frac{4^{\backslash 7}}{9} - 3\frac{6^{\backslash 9}}{7} = 6\frac{28}{63} - 3\frac{54}{63} =\]

\[= 5\frac{91}{63} - 3\frac{54}{63} = 2\frac{37}{63}\]

\[3)\ 10\frac{11^{\backslash 3}}{24} - 8\frac{19^{\backslash 2}}{36} =\]

\[= 10\frac{33}{72} - 8\frac{38}{72} =\]

\[= 9\frac{105}{72} - 8\frac{38}{72} = 1\frac{67}{72}\]

\[4)\ 9\frac{1^{\backslash 2}}{6} - 5\frac{3^{\backslash 3}}{4} = 9\frac{2}{12} - 5\frac{9}{12} =\]

\[= 8\frac{14}{12} - 5\frac{9}{12} = 3\frac{5}{12}\]

\[\boxed{\mathbf{280\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 3\frac{1}{12} - \frac{1^{\backslash 2}}{6} = 2\frac{13}{12} - \frac{2}{12} =\]

\[= 2\frac{11}{12}\]

\[2)\ 8\frac{7^{\backslash 2}}{30} - 2\frac{9^{\backslash 3}}{20} = 8\frac{14}{60} - 2\frac{27}{60} =\]

\[= 7\frac{74}{60} - 2\frac{27}{60} = 5\frac{47}{60}\]

\[3)\ 7\frac{10^{\backslash 2}}{51} - 4\frac{21^{\backslash 3}}{34} =\]

\[= 7\frac{20}{102} - 4\frac{63}{102} =\]

\[= 6\frac{\ 122}{102} - 4\frac{63}{102} = 2\frac{59}{102}\ \]

\[4)\ 5\frac{1^{\backslash 2}}{4} - 1\frac{3}{8} = 5\frac{2}{8} - 1\frac{3}{8} =\]

\[= 4\frac{10}{8} - 1\frac{3}{8} = 3\frac{7}{8}\]

\[\boxed{\mathbf{280}\mathbf{.}}\]