Решебник по математике 6 класс Мерзляк ФГОС Задание 279

\[\boxed{\mathbf{279\ (280)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 3\frac{1}{12} - \frac{1^{\backslash 2}}{6} = 2\frac{13}{12} - \frac{2}{12} =\]

\[= 2\frac{11}{12}\]

\[2)\ 8\frac{7^{\backslash 2}}{30} - 2\frac{9^{\backslash 3}}{20} = 8\frac{14}{60} - 2\frac{27}{60} =\]

\[= 7\frac{74}{60} - 2\frac{27}{60} = 5\frac{47}{60}\]

\[3)\ 7\frac{10^{\backslash 2}}{51} - 4\frac{21^{\backslash 3}}{34} =\]

\[= 7\frac{20}{102} - 4\frac{63}{102} =\]

\[= 6\frac{\ 122}{102} - 4\frac{63}{102} = 2\frac{59}{102}\ \]

\[4)\ 5\frac{1^{\backslash 2}}{4} - 1\frac{3}{8} = 5\frac{2}{8} - 1\frac{3}{8} =\]

\[= 4\frac{10}{8} - 1\frac{3}{8} = 3\frac{7}{8}\]

\[\boxed{\mathbf{279\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 1^{\backslash 55} - \frac{13}{55} = \frac{55 - 13}{55} = \frac{42}{55}\]

\[2)\ 6 - \frac{6}{20} = 5\frac{20}{20} - \frac{9}{20} = 5\frac{11}{20}\]

\[3)\ 10 - 5\frac{12}{35} = 9\frac{35}{35} - 5\frac{12}{35} =\]

\[= 4\frac{23}{35}\]

\[4)\ 8 - 4\frac{5}{22} = 7\frac{22}{22} - 4\frac{5}{22} =\]

\[= 3\frac{17}{22}\]

\[\boxed{\mathbf{279}\mathbf{.}}\]

\[ABCD - квадрат:\]

\[все\ углы\ прямые;\]

\[все\ стороны\ равны.\]