Решебник по математике 6 класс Ерина Никольский рабочая тетрадь Часть 1, 2 Часть 1 | Страница 57

\[\mathbf{Страница\ 57.}\]

\[\boxed{\mathbf{4.}}\]

\[\textbf{а)} - 72\ :18 = - 4\]

\[30\ :( - 15) = - 2\]

\[- 45\ :( - 9) = 5\]

\[360\ :( - 9) = - 40\]

\[\textbf{б)} - 20\ :4 = - 5\]

\[- 24\ :( - 2) = 12\]

\[- 36\ :( - 4) = 9\]

\[14\ :( - 7) = - 2\]

\[\textbf{в)}\ 77\ :( - 7) = - 11\]

\[- 30\ :2 = - 15\]

\[- 45\ :( - 5) = 9\]

\[0\ :( - 3) = 0\]

\[\boxed{\mathbf{5.}}\]

\[\textbf{а)}\ 7\ :3 = \frac{7}{3} = 2\frac{1}{3}\]

\[4\ :20 = \frac{4}{20} = \frac{1}{5}\]

\[8\ :5 = \frac{8}{5} = 1\frac{3}{5}\]

\[\frac{3}{8}\ :\frac{1}{4} = \frac{3}{8} \cdot 4 = \frac{3}{2} = 1,5\]

\[\frac{1}{5}\ :\frac{3}{4} = \frac{1}{5} \cdot \frac{4}{3} = \frac{4}{15}\]

\[\frac{4}{15}\ :3\frac{1}{15} = \frac{4}{15}\ :\frac{46}{15} =\]

\[= \frac{4}{15} \cdot \frac{15}{46} = \frac{2}{23}\]

\[\textbf{б)}\ 6\ :\frac{6}{11} = 6 \cdot \frac{11}{6} = 11\]

\[3\frac{3}{7}\ :8 = \frac{24}{7} \cdot \frac{1}{8} = \frac{3}{7}\]

\[3\frac{1}{2}\ :\frac{2}{3} = \frac{7}{2} \cdot \frac{3}{2} = \frac{21}{4} = 5\frac{1}{4}\]

\[\frac{3}{16}\ :\frac{5}{12} = \frac{3}{16} \cdot \frac{12}{5} = \frac{9}{20}\]

\[3\frac{1}{4}\ :1 = 3\frac{1}{4}\]

\[1\frac{2}{3}\ :1\frac{1}{10} = \frac{5}{3}\ :\frac{11}{10} = \frac{5}{3} \cdot \frac{10}{11} =\]

\[= \frac{50}{33} = 1\frac{17}{33}\]

\[\boxed{\mathbf{6.}}\]

\[a\ :b\]

\[5\frac{1}{5};\ - 2;\ - 7;\ \ 2;\ \ 1;\ \ 2;\ \]

\[\frac{4}{25};\ \ 1\frac{3}{7};\ \ 2;\ \ 2.\]

\[\boxed{\mathbf{7.}}\]

\[\textbf{а)}\ x\ :5 = - 7\]

\[x = - 7 \cdot 5\]

\[x = - 35.\]

\[Ответ:\ - 35.\]

\[\textbf{б)}\ y \cdot ( - 7) = 56\]

\[y = 56\ :( - 7)\]

\[y = - 8.\]

\[Ответ:\ - 8.\]

\[\textbf{в)}\ a - 4 = - 11\]

\[a = - 11 + 4\]

\[a = - 7.\ \]

\[Ответ:\ - 7.\]