Решебник по математике 5 класс Виленкин Часть 1, 2 Часть 2. Параграф 5. Обыкновенные дроби Задание 366

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\[\textbf{а)}\ 4\ :2 = 2\]

\[\frac{3}{2} = \frac{3 \cdot 2}{2 \cdot 2} = \frac{6}{4};\ \]

\[\textbf{б)}\ 10\ :5 = 2\]

\[\frac{6}{5} = \frac{6 \cdot 2}{5 \cdot 2} = \frac{12}{10};\ \]

\[\textbf{в)}\ 12\ :6 = 2\]

\[\frac{7}{6} = \frac{7 \cdot 2}{6 \cdot 2} = \frac{14}{12};\ \]

\[\textbf{г)}\ 100\ :5 = 20\]

\[\frac{1}{5} = \frac{1 \cdot 20}{5 \cdot 20} = \frac{20}{100};\ \]

\[\textbf{д)}\ 30\ :5 = 6\]

\[\frac{4}{5} = \frac{4 \cdot 6}{5 \cdot 6} = \frac{24}{30};\ \]

\[\textbf{е)}\ 1\ 000\ :50 = 20\]

\[\frac{7}{50} = \frac{7 \cdot 20}{50 \cdot 20} = \frac{140}{1\ 000}\text{.\ \ }\]