Решебник по математике 5 класс Мерзляк ФГОС Задание 1140

 

\[\boxed{\mathbf{1140\ (1140)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 37,5\ :1,5 = 375\ :15 =\]

\[= 25\ (м) - ширина\ поля.\]

\[2)\ 37,5 \cdot 25 = 937,5\ \left( м^{2} \right) -\]

\[площадь\ поля.\]

\[3)\ 937,5\ м^{2} = 9,375\ а.\]

\[9,375 \cdot 42,8 = 401,25\ (ц) -\]

\[собрал\ со\ всего\ поля.\]

\[401,25\ ц = 40,125\ т =\]

\[= 40125\ кг = 40\ т\ 1\ ц\ 25\ кг.\]

\[Ответ:40\ т\ 1\ ц\ 25\ кг.\]

\[\boxed{\mathbf{1140}\mathbf{.}\mathbf{\ }}\]

\[1)\ \frac{25}{27}x = \frac{5}{18}\text{\ \ \ }\]

\[x = \frac{5}{18}\ :\frac{25}{27}\]

\[x = \frac{5}{18} \cdot \frac{27}{25}\]

\[x = \frac{3}{10}\]

\[Ответ:\frac{3}{10}.\]

\[2)\ 4x = \frac{5}{7}\text{\ \ \ \ }\]

\[x = \frac{5}{7}\ :4\]

\[x = \frac{5}{7} \cdot \frac{1}{4}\]

\[x = \frac{5}{7 \cdot 4}\]

\[x = \frac{5}{28}\]

\[Ответ:\frac{5}{28}.\]

\[4)\ x\ :2\frac{2}{15} = 1\frac{9}{16}\text{\ \ \ \ }\]

\[x = 1\frac{9}{16} \cdot 2\frac{2}{15}\]

\[x = \frac{25}{16} \cdot \frac{32}{15}\]

\[x = \frac{10}{3}\]

\[x = 3\frac{1}{3}\]

\[Ответ:3\frac{1}{3}.\]

\[5)\ 4\frac{4}{9}\ :x = \frac{5}{27}\text{\ \ \ \ \ }\]

\[x = 4\frac{4}{9}\ :\frac{5}{27}\]

\[x = \frac{40}{9} \cdot \frac{27}{5}\]

\[x = 24\]

\[Ответ:24.\]