Решебник по математике 5 класс Мерзляк ФГОС Задание 1139

 

\[\boxed{\mathbf{1139\ (1139)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 400 \cdot 2,3 = 920\ (ц) -\]

\[капусты\ собрала\ Коза.\]

\[2)\ 92\ т\ :3,5 = 920\ :35 \approx\]

\[\approx 27\ (машин).\]

\[Ответ:нужно\ 27\ машин.\ \]

\[\boxed{\mathbf{1139}\mathbf{.}\mathbf{\ }}\]

\[1)\ \frac{2}{7}x = \frac{9}{14}\]

\[x = \frac{9}{14}\ :\frac{2}{7}\]

\[x = \frac{9}{14} \cdot \frac{7}{2}\]

\[x = \frac{9}{4}\]

\[x = 2\frac{1}{4}\]

\[Ответ:2\frac{1}{4}.\]

\[2)\ \frac{3}{8}x = 6\]

\[x = 6\ :\frac{3}{8}\]

\[x = 6 \cdot \frac{8}{3}\]

\[x = 16\]

\[Ответ:16.\]

\[3)\ 3x = \frac{2}{9}\]

\[x = \frac{2}{9}\ :3\]

\[x = \frac{2}{9} \cdot \frac{1}{3}\]

\[x = \frac{2}{9 \cdot 3}\]

\[x = \frac{2}{27}\]

\[Ответ:\frac{2}{27}.\]

\[4)\ x\ :\frac{6}{11} = \frac{3}{7}\]

\[x = \frac{3}{7} \cdot \frac{6}{11}\]

\[x = \frac{3 \cdot 6}{7 \cdot 11}\]

\[x = \frac{18}{77}\]

\[Ответ:\ \frac{18}{77}.\]

\[5)\frac{18}{49}\ :x = \frac{6}{35}\]

\[x = \frac{18}{49}\ :\frac{6}{35}\]

\[x = \frac{18}{49} \cdot \frac{35}{6}\]

\[x = \frac{15}{7}\]

\[x = 2\frac{1}{7}\]

\[Ответ:2\frac{1}{7}.\]

\[6)\ \frac{3}{8}x = 2,4\]

\[x = \frac{24}{10}\ :\frac{3}{8}\]

\[x = \frac{12}{5} \cdot \frac{8}{3}\]

\[x = \frac{32}{5}\]

\[x = 6\frac{2}{5}\]

\[Ответ:6\frac{2}{5}.\]