Решебник по математике 5 класс Мерзляк ФГОС Задание 1137

 

\[\boxed{\mathbf{1137\ (1137)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 896 - 392 = 504\ (ц) - на\ \]

\[столько\ больше\ со\ второго\ \]

\[поля.\]

\[2)\ 504\ :18 = 28\ \left( \frac{ц}{га} \right) -\]

\[урожайность.\]

\[3)\ 392\ :28 = 14\ (га) - первое\ \]

\[поле.\]

\[4)\ 896\ :28 = 32\ (га) - второе\ \]

\[поле.\]

\[Ответ:14\ га\ и\ 32\ га.\]

\[\boxed{\mathbf{1137}\mathbf{.}\mathbf{\ }}\]

\[1)\ 3\frac{3}{4}\ :\frac{3}{8}\ :1\frac{3}{7} = \frac{18}{4}\ :\frac{3}{8}\ :\frac{10}{7} =\]

\[= \frac{18}{4} \cdot \frac{8}{3} \cdot \frac{7}{10} = \frac{18 \cdot 8 \cdot 7}{4 \cdot 3 \cdot 10} = 7\]

\[2)\ 3\ \frac{3}{4}\ :\left( \frac{3}{8} \cdot 1\frac{3}{7} \right) =\]

\[= \frac{15}{4}\ :\left( \frac{3 \cdot 7}{8 \cdot 10} \right) = \frac{15 \cdot 8 \cdot 10}{4 \cdot 3 \cdot 7} =\]

\[= \frac{100}{7} = 14\frac{2}{7}\]

\[3)\ 1\frac{7}{9} \cdot \frac{15}{32}\ :1\frac{19}{36} = \frac{16}{9} \cdot \frac{15}{32}\ :\frac{55}{36} =\]

\[= \frac{16 \cdot 15 \cdot 36}{9 \cdot 32 \cdot 55} = \frac{6}{11}\]

\[4)\ 1\frac{7}{9} \cdot \left( \frac{15}{32}\ :1\frac{19}{36} \right) =\]

\[= \frac{16}{9} \cdot \left( \frac{15}{32}\ :\frac{55}{36} \right) =\]

\[= \frac{16}{9} \cdot \left( \frac{15 \cdot 36}{32 \cdot 55} \right) = \frac{16 \cdot 15 \cdot 36}{9 \cdot 32 \cdot 55} =\]

\[= \frac{6}{11}\]

\[5)\ 2\frac{1}{4}\ :1\frac{4}{11} - \frac{3}{8}\ :\frac{7}{8} =\]

\[= \frac{9}{4}\ :\frac{15}{11} - \frac{3}{8} \cdot \frac{8}{7} = \frac{9 \cdot 11}{4 \cdot 15} - \frac{3 \cdot 8}{8 \cdot 7} =\]

\[= \frac{33^{\backslash 7}}{20} - \frac{3^{\backslash 20}}{7} = \frac{231 - 60}{140} =\]

\[= \frac{171}{140} = 1\frac{31}{140}\]

\[6)\ \left( 3\frac{1}{6} - 5\frac{1}{6}\ :4\frac{2}{15} \right) \cdot \frac{3}{92} =\]

\[= \left( \frac{19}{6} - \frac{31}{6}\ :\frac{62}{15} \right) \cdot \frac{3}{92} =\]

\[= \left( \frac{19}{6} - \frac{31 \cdot 15}{6 \cdot 62} \right) \cdot \frac{3}{92} =\]

\[= \left( \frac{19}{6} - \frac{5}{4} \right) \cdot \frac{3}{92} =\]

\[= \frac{19 \cdot 3}{6 \cdot 92} - \frac{5 \cdot 3}{4 \cdot 92} = \frac{19}{184} - \frac{15}{368} =\]

\[= \frac{38 - 15}{368} = \frac{23}{368} = \frac{1}{16}\]