Решебник по математике 5 класс Мерзляк ФГОС Задание 1136

\[\boxed{\mathbf{1136\ (1136)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 4x > 14\]

\[x > 14\ :4\]

\[x > 3,5\]

\[то\ есть\ наименьшее\ \]

\[натуральное\ x = 4.\]

\[2)\ 7x > 40\frac{7}{9}\]

\[x > 40\frac{7}{9}\ :7\]

\[x > 5,8.\]

\[40\frac{7}{9}\ :7 = \frac{367}{9} \cdot \frac{1}{7} = \frac{367}{63} \approx 5,8.\]

\[то\ есть\ наименьшее\ \]

\[натуральное\ x = 6.\]

\[\boxed{\mathbf{1136}\mathbf{.}\mathbf{\ }}\]

\[1)\ 16\ :\frac{4}{11} = 16 \cdot \frac{11}{4} = 4 \cdot 11 =\]

\[= 44\]

\[2)\ \frac{9}{16}\ :6 = \frac{9}{16} \cdot \frac{1}{6} = \frac{3 \cdot 1}{16 \cdot 2} = \frac{3}{32}\]

\[3)\ 1\frac{5}{9}\ :1\frac{8}{27} = \frac{14}{9}\ :\frac{35}{27} =\]

\[= \frac{14}{9} \cdot \frac{27}{35} = \frac{2 \cdot 3}{1 \cdot 5} = \frac{6}{5} = 1\frac{1}{5}\]

\[4)\ 2\frac{4}{7}\ :1\frac{1}{35} = \frac{18}{7}\ :\frac{36}{35} =\]

\[= \frac{18}{7} \cdot \frac{35}{36} = \frac{1 \cdot 5}{1 \cdot 2} = \frac{5}{2} = 2\frac{1}{2}\]