Решебник по математике 5 класс Мерзляк ФГОС Задание 1058

\[\boxed{\mathbf{1058\ (1058)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[100\% - 29\% =\]

\[= 71\% - занимает\ Мировой\ \]

\[океан.\]

\[Ответ:71\%.\]

\[\boxed{\mathbf{1058}\mathbf{.}\mathbf{\ }}\]

\[1)\ \left( \frac{11}{18} - \frac{4^{\backslash 2}}{9} \right) \cdot \frac{3}{16} =\]

\[= \left( \frac{11}{18} - \frac{8}{18} \right) \cdot \frac{3}{16} = \frac{3}{18} \cdot \frac{3}{16} =\]

\[= \frac{1}{6} \cdot \frac{3}{16} = \frac{3}{96} = \frac{1}{32}\]

\[3)\ 1\frac{3}{5} \cdot \left( \frac{3}{4} + 1\frac{3}{8} \right) =\]

\[= \frac{8}{5} \cdot \left( \frac{3^{\backslash 2}}{4} + \frac{11}{8} \right) = \frac{8}{5} \cdot \frac{6 + 11}{8} =\]

\[= \frac{8 \cdot 17}{5 \cdot 8} = \frac{17}{5} = 3\frac{2}{5}\]

\[5)\ \]

\[= \frac{12^{\backslash 2}}{5} - \frac{3}{10} = \frac{24 - 3}{10} = \frac{21}{10} =\]

\[= 2\frac{1}{10}\]

\[6)\ \left( 8 - 2\frac{1}{7} \cdot 3\frac{1}{9} \right) \cdot \frac{27}{44} =\]

\[= \left( 8 - \frac{15}{7} \cdot \frac{28}{9} \right) \cdot \frac{27}{44} =\]

\[= \left( 8 - \frac{15 \cdot 28}{7 \cdot 9} \right) \cdot \frac{27}{44} =\]