Решебник по математике 5 класс Мерзляк ФГОС Задание 1057

 

\[\boxed{\mathbf{1057\ (1057)}.\ Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 76\ :100 \cdot 1 = 7,6\]

\[2)\ 300\ :100 \cdot 7 = 21\]

\[3)\ 10\ :100 \cdot 26 = 0,1 \cdot 26 = 2,6\]

\[4)\ 120\ :100 \cdot 30 = 1,2 \cdot 30 = 36\]

\[5)\ 16,5\ :100 \cdot 94 = 0,165 \cdot 94 =\]

\[= 15,51\]

\[6)\ 62\ :100 \cdot 156 = 0,62 \cdot 156 =\]

\[= 96,72\]

\[\boxed{\mathbf{1057}\mathbf{.}\mathbf{\ }}\]

\[1)\ \frac{13}{30} \cdot \frac{18}{65} = \frac{13 \cdot 18}{30 \cdot 65} = \frac{1 \cdot 3}{5 \cdot 5} =\]

\[= \frac{3}{25}\ (К)\]

\[2)\ \frac{5}{24} \cdot \frac{9}{20} = \frac{5 \cdot 9}{24 \cdot 20} = \frac{1 \cdot 3}{8 \cdot 4} =\]

\[= \frac{3}{32}\ (О)\]

\[3)\ \frac{4}{9} \cdot 6 = \frac{4 \cdot 6}{9} = \frac{4 \cdot 2}{3} = \frac{8}{3} =\]

\[= 2\frac{2}{3}\ (Л)\]

\[4)\ \frac{27}{35} \cdot \frac{14}{45} = \frac{27 \cdot 14}{35 \cdot 45} = \frac{3 \cdot 2}{5 \cdot 5} =\]

\[= \frac{6}{25}\ (М)\]

\[5)\ \frac{5}{42} \cdot \frac{7}{25} = \frac{5 \cdot 7}{42 \cdot 25} = \frac{1 \cdot 1}{6 \cdot 5} =\]

\[= \frac{1}{30}\ (О)\]

\[6)\ \frac{3}{25} \cdot \frac{5}{36} = \frac{3 \cdot 5}{25 \cdot 36} = \frac{1 \cdot 1}{5 \cdot 12} =\]

\[= \frac{1}{60}\ (Г)\]

\[7)\ 1\frac{6}{11} \cdot 1\frac{21}{34} = \frac{17}{11} \cdot \frac{55}{34} = \frac{1 \cdot 5}{1 \cdot 2} =\]

\[= \frac{5}{2} = 2\frac{1}{2}\ (О)\]

\[8)\ 2\frac{7}{8} \cdot 2\frac{2}{23} = \frac{23}{8} \cdot \frac{48}{23} = 1 \cdot 6 =\]

\[= 6\ (Р)\]

\[9)\ \frac{1}{3} \cdot \frac{3}{20} = \frac{1}{20}\ (О)\]

\[10)\ 1\frac{4}{15} \cdot 1\frac{7}{38} = \frac{19}{15} \cdot \frac{45}{38} =\]

\[= \frac{1 \cdot 3}{1 \cdot 2} = \frac{3}{2} = 1\frac{1}{2}\ (В)\]

\[Математик\ и\ педагог:\]

\[КОЛМОГОРОВ.\]