Решебник по геометрии 9 класс Мерзляк Задание 189

\[R_{1} = \frac{8}{2\sin{45{^\circ}}} = 4\ :\frac{\sqrt{2}}{2} = 4\sqrt{2};\ \ \ \]

\[r_{1} = \frac{8}{2\ tg\ 45{^\circ}} = 4;\]

\[a_{2} = 4 \bullet 2\sin{45{^\circ}} = 8 \bullet \frac{\sqrt{2}}{2} = 4\sqrt{2};\ \ \ \]

\[r_{2} = \frac{4\sqrt{2}}{2\ tg\ 45{^\circ}} = 2\sqrt{2};\]

\[a_{3} = \sqrt{2} \bullet 2\ tg\ 45{^\circ} = 2\sqrt{2};\ \ \ \]

\[R_{3} = \frac{2\sqrt{2}}{2\sin{45{^\circ}}} = \sqrt{2}\ :\frac{\sqrt{2}}{2} = 2.\]