\[1)\ AB = 6\ см;BC = 10\ см;\]
\[AC = 14\ см;\ A_{1}B_{1} = 9\ см;\ \]
\[B_{1}C_{1} = 15\ см;\ A_{1}C_{1} = 21\ см:\]
\[\frac{\text{AB}}{A_{1}B_{1}} = \frac{6}{9} = \frac{2}{3};\ \ \ \]
\[\frac{\text{BC}}{B_{1}C_{1}} = \frac{10}{15} = \frac{2}{3};\ \ \ \]
\[\frac{\text{AC}}{A_{1}C_{1}} = \frac{14}{21} = \frac{2}{3};\]
\[\mathrm{\Delta}ABC\sim\mathrm{\Delta}A_{1}B_{1}C_{1} - третий\ признак.\]
\[Ответ:\ \ да.\]
\[2)\ AB = 1,3\ см;BC = 2,5\ см;\text{\ \ \ }\]
\[AC = 3,2\ см;\ A_{1}B_{1} = 26\ см;\text{\ \ \ }\]
\[B_{1}C_{1} = 50\ см;A_{1}C_{1} = 60\ см:\]
\[\frac{\text{AB}}{A_{1}B_{1}} = \frac{1,3}{26} = \frac{1}{20};\]
\[\frac{\text{AC}}{A_{1}C_{1}} = \frac{3,2}{60} = \frac{4}{75}.\]
\[Ответ:\ \ нет.\]