Решебник по геометрии 7 класс Атанасян ФГОС Задание 1345

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\[\textbf{а)}\ k = \frac{8}{18} = \frac{4}{9}.\]

\[z = 12 \cdot \frac{4}{9} = \frac{16}{3} = 5\frac{1}{3};\]

\[x = 15 \cdot \frac{4}{9} = \frac{20}{3} = 6\frac{2}{3};\]

\[y = 21 \cdot \frac{4}{9} = \frac{28}{3} = 9\frac{1}{3}.\]

\[\alpha = 60{^\circ};\]

\[\beta = 110{^\circ}.\]

\[\textbf{б)}\ k = \frac{12}{18} = \frac{2}{3}.\]

\[x = 21 \cdot \frac{2}{3} = 14;\]

\[z = 27 \cdot \frac{2}{3} = 18;\]

\[y = 18 \cdot \frac{3}{2} = 27.\]

\[\alpha = 50{^\circ};\]

\[\beta = 70{^\circ}.\]