\[Схематический\ рисунок.\]
\[Дано:\ \ \]
\[AB = 32\ см;\]
\[AE = EC;\]
\[DF = FB;\]
\[EF = 18\ см.\]
\[Найти:\]
\[\text{CD.}\]
\[Решение.\]
\[1)\ Отрезок\ EF:\]
\[EF = EC + CD + DF\]
\[EC + DF = EF - CD\]
\[EC + DF = 18 - CD.\]
\[2)\ Отрезок\ AB:\]
\[AB = AE + EC + CD + DF + FB\]
\[AB = EC + EC + CD + DF + DF\]
\[AB = 2(EC + DF) + CD\]
\[AB = 2(18 - CD) + CD\]
\[32 = 36 - 2CD + CD\]
\[CD = 4\ см.\]
\[\ Ответ:\ \ 4\ см.\]