\[Схематический\ рисунок.\]
\[Дано:\ \ \]
\[AB = 20\ см;\]
\[1)\ AC = BC + 5\ см;\]
\[2)\ AC = BC\ :4;\]
\[3)\ AC\ :BC = 9\ :11.\]
\[Найти:\]
\[AC;\ BC.\]
\[Решение.\]
\[AB = AC + BC\]
\[1)\ 20 = BC + 5 + BC\]
\[2BC = 15\]
\[BC = 7,5\]
\[AC = 7,5 + 5 = 12,5\ см.\]
\[2)\ 20 = \frac{\text{BC}}{4} + BC\ \ \ | \cdot 4\]
\[80 = BC + 4BC\]
\[5BC = 80;\]
\[BC = 16\ см.\]
\[AC = \frac{16}{4} = 4\ см.\]
\[3)\ AC = \frac{9}{11}BC:\]
\[20 = \frac{9}{11}BC + BC\]
\[220 = 9BC + 11BC\]
\[20BC = 220\]
\[BC = 11\ см.\]
\[AC = \frac{9}{11} \bullet 11 = 9\ см.\]
\[Ответ:\ \ 1)\ 12,5\ см,\ 7,5\ см;\ \]
\(2)\ 4\ см,\ 16\ см;\ 3)\ 9\ см,\ 11\ см.\)