\[Схематический\ рисунок.\]
\[Дано:\ \ \]
\[AB = a;\]
\[AC = 2CD;\]
\[CD = 2DB;\]
\[AE = EC;\]
\[CF = FD;\]
\[DT = TB.\]
\[Найти:\]
\[1)\ AF;\]
\[2)\ ET.\]
\[Решение.\]
\[AB = AC + CD + DB = a\]
\[2CD + 2DB + DB = a\]
\[4DB + 3DB = a\]
\[7DB = a\]
\[DB = \frac{a}{7}.\]
\[1)\ AF = AC + CF = 2CD + \frac{1}{2}\text{CD}\]
\[AF = 2,5CD = 5DB = \frac{5a}{7}.\]
\[2)\ ET = EC + CD + DT\]
\[ET = \frac{1}{2}AC + 2DB + \frac{1}{2}\text{DB}\]
\[ET = CD + 2,5DB = 2DB + 2,5DB\]
\[ET = 4,5DB = 4,5 \bullet \frac{a}{7} = \frac{9a}{14}.\]
\[Ответ:\ \ 1)\ \frac{5a}{7};\ 2)\ \frac{9a}{14}.\]