\[Схематический\ рисунок.\]
\[Дано:\ \ \]
\[\angle ABC = 70{^\circ};\]
\[BD\bot BA;\]
\[BF\bot BC.\]
\[Найти:\]
\[\angle DBF;\ \]
\[\angle ABF.\]
\[Решение:\]
\[1)\ \angle ABD = \angle ABC + \angle CBD\]
\[90{^\circ} = 70{^\circ} + \angle CBD\]
\[\angle CBD = 20{^\circ}.\]
\[2)\ \angle CBF = \angle CBD + \angle DBF\]
\[90{^\circ} = 20{^\circ} + \angle DBF\]
\[\angle DBF = 70{^\circ}.\]
\[3)\ \angle ABF = \angle ABD + \angle DBF\]
\[\angle ABF = 90{^\circ} + 70{^\circ} = 160{^\circ}.\]
\[Ответ:\ \ \angle DBF = 70{^\circ};\ \]
\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \angle ABF = 160{^\circ}.\]