\[Рисунок\ в\ учебнике.\]
\[Дано:\ \ \]
\[\angle DBO = 54{^\circ};\]
\[AC\bot DK;\ \]
\[OB\bot BF.\]
\[Найти:\]
\[\angle ABF.\]
\[Решение.\]
\[180{^\circ} = 54{^\circ} + 90{^\circ} + \angle KBF\]
\[\angle KBF = 36{^\circ}.\]
\[2)\ \angle ABF = \angle ABK + \angle KBF\]
\[\angle ABF = 90{^\circ} + 36{^\circ} = 126{^\circ}.\]
\[Ответ:\ \ 126{^\circ}.\]