Решебник по геометрии 11 класс. Атанасян ФГОС 624

Авторы:
Год:2023
Тип:учебник

624

\[\boxed{\mathbf{624.}ОК\ ГДЗ\ –\ домашка\ на\ 5}\]

\[Дано:\ \ \]

\[Решение.\]

\[\textbf{а)}\ \overrightarrow{\text{ON}} = \overrightarrow{\text{OM}} + \overrightarrow{\text{MN}}:\]

\[\overrightarrow{\text{MN}} = \overrightarrow{\text{ON}} - \overrightarrow{\text{OM}}.\]

\[\overrightarrow{\text{OP}} = \overrightarrow{\text{ON}} + \overrightarrow{\text{NP}} = \overrightarrow{\text{ON}} + 2\overrightarrow{\text{MN}};\]

\[\overrightarrow{\text{OP}} = \overrightarrow{\text{ON}} + 2\left( \overrightarrow{\text{ON}} - \overrightarrow{\text{OM}} \right) =\]

\[= 3\overrightarrow{\text{ON}} - 2\overrightarrow{\text{OM}}.\]

\[\textbf{б)}\ \overrightarrow{\text{MP}} = - \frac{1}{2}\overrightarrow{\text{PN}} = \frac{1}{2}\overrightarrow{\text{NP}}:\]

\[PM = MN;\ \ \overrightarrow{\text{PM}} = - \overrightarrow{\text{NM}}.\]

\[Получаем:\]

\[2\overrightarrow{\text{OM}} = \overrightarrow{\text{OP}} + \overrightarrow{\text{PM}} + \overrightarrow{\text{ON}} + \overrightarrow{\text{NM}}\]

\[\overrightarrow{\text{OP}} = 2\overrightarrow{\text{OM}} - \overrightarrow{\text{ON}}.\]

\[\textbf{в)}\ \overrightarrow{\text{ON}} = \overrightarrow{\text{OM}} + \overrightarrow{\text{MN}};\ \]

\[\ \overrightarrow{\text{MP}} = k \bullet \overrightarrow{\text{MN}}:\ \]

\[\overrightarrow{\text{OP}} = \overrightarrow{\text{ON}} + \overrightarrow{\text{NP}} =\]

\[= \overrightarrow{\text{OM}} + \overrightarrow{\text{MN}} + \overrightarrow{\text{NP}} =\]

\[= \overrightarrow{\text{OM}} + \overrightarrow{\text{MP}} = \overrightarrow{\text{OM}} + k \bullet \overrightarrow{\text{MN}}.\]

\[\overrightarrow{\text{MN}} = \overrightarrow{\text{MO}} + \overrightarrow{\text{ON}}:\]

\[\overrightarrow{\text{OP}} = \overrightarrow{\text{OM}} + k\overrightarrow{\text{MO}} + k\overrightarrow{\text{ON}} =\]

\[= k\overrightarrow{\text{ON}} + \overrightarrow{\text{OM}} - k\overrightarrow{\text{OM}} =\]

\[= k\overrightarrow{\text{ON}} + (1 - k)\overrightarrow{\text{OM}}.\]

\[Ответ:\ \ а)\ 3\overrightarrow{\text{ON}} - 2\overrightarrow{\text{OM}};\ \ \]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ б)\ 2\overrightarrow{\text{OM}} - \overrightarrow{\text{ON}};\ \ \]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ в)\ k\overrightarrow{\text{ON}} + (1 - k)\overrightarrow{\text{OM}}.\]

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