\[\boxed{\mathbf{352.}ОК\ ГДЗ\ –\ домашка\ на\ 5}\]
\[Дано:\]
\[ASB - осевое\ сечение;\]
\[S_{\text{ASB}} = 6\ дм^{2};\]
\[S_{осн} = 8\ дм^{2}.\]
\[Найти:\]
\[h = SO.\]
\[Решение.\]
\[S_{\text{ASB}} = \frac{1}{2}SO \cdot AB;\ \ AB = 2r:\]
\[S_{\text{ASB}} = \frac{SO \cdot 2r}{2} = rh\]
\[rh = 6\]
\[h = \frac{6}{r}.\]
\[S_{осн} = \pi r^{2}\]
\[\pi r^{2} = 8\]
\[r = \sqrt{\frac{8}{\pi}} = 2\sqrt{\frac{2}{\pi}}.\]
\[h = \frac{6\sqrt{\pi}}{2\sqrt{2}} = 3\sqrt{\frac{\pi}{2}}\ дм.\]
\[Ответ:\ 3\sqrt{\frac{\pi}{2}}\ дм.\]