ГДЗ по алгебре 9 класс Макарычев Задание 488

 

\[\boxed{\text{488\ (488).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ \ xy < 4\]

\[y < \frac{4}{x}\]

\[\textbf{б)}\ xy > - 6\]

\[y > - \frac{6}{x}\]

\[\boxed{\text{488.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]

\[( - 4,3;\ - 14,3);\ \ (2,3; - 7,7).\]

\[\textbf{б)}\ \left\{ \begin{matrix} (x - 2)^{2} + y^{2} = 9 \\ y = x^{2} - 4x + 4\ \ \ \\ \end{matrix} \right.\ \]

\[(0,4;2,5);\ \ (3,6;2,5).\]

\[\textbf{в)}\ \ \left\{ \begin{matrix} x^{2} + y^{2} = 25 \\ y = 2x^{2} - 14\ \\ \end{matrix} \right.\ \]

\[(3;4);\ \ ( - 3;4);\ \ ( - 2,2;\ - 4,5);\ \ \]

\[(2,2;4,5).\]

\[( - 3;\ - 1);\ \ ( - 1;\ - 3);\ \ (1;3);\ \]

\[(3;1).\]

\[( - 1;9);\ \ (8;0).\]

\[\textbf{е)}\ \left\{ \begin{matrix} y = - x^{2} + 4 \\ y = |x|\text{\ \ \ \ \ \ \ \ \ \ } \\ \end{matrix} \right.\ \]

\[( - 1,6;1,6);\ \ (1,6;1,6).\]