Решебник по алгебре 9 класс Макарычев Задание 399

 

\[\boxed{\text{399\ (399).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ 3x + 0y = 12\]

\[3x = 12\]

\[x = 4.\]

\[\textbf{б)}\ 0x + y = 1\]

\[y = 1.\]

\[\textbf{в)}\ x = 5\ \]

\[\textbf{г)}\ y = 1,5\]

\[\textbf{д)}\ (x - 2)(y - 3) = 0\]

\[x = 2;\ \ \ y = 3.\]

\[\textbf{е)}\ (x + 3)(y + 1) = 0\]

\[x = - 3;\ \ y = - 1.\]

\[\textbf{ж)}\ |x| = 2\]

\[x = 2;\ \ \ x = - 2.\]

\[\textbf{з)}\ |y| = 3\]

\[y = 3;\ \ y = - 3.\ \]

\[\boxed{\text{399.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\ \]

\[( - 3,6;1,6);\ \ \ (1,6;\ - 3,6):\]

\[нет\ решений.\]

\[(1;3);( - 2; - 1,6).\]

\[( - 3;9);(3;9);( - 0,5;0,1).\]