\[\boxed{\text{169\ (169).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[\mathbf{При\ любом\ нечетном\ }\mathbf{\text{n\ }}\mathbf{и\ }\]
\[\mathbf{четном\ }\mathbf{\text{a\ }}\mathbf{верно\ равенство:}\]
\[\sqrt[\mathbf{n}]{\mathbf{- a}}\mathbf{= -}\sqrt[\mathbf{n}]{\mathbf{a}}\mathbf{.}\]
Решение.
\[\textbf{а)}\ \sqrt[3]{- 31} = - \sqrt[3]{31};\]
\[\textbf{б)}\ \sqrt[5]{- 17} = - \sqrt[5]{17};\]
\[\textbf{в)}\ \sqrt[11]{- 2} = - \sqrt[11]{2};\]
\[\textbf{г)}\ \sqrt[17]{- 6} = - \sqrt[17]{6}.\]
\[\boxed{\text{169.}\text{\ }\text{ОК\ ГДЗ\ -\ домашка\ на\ 5}}\]
\[\textbf{а)}\ y = \frac{4}{x - 3}\]
\[\textbf{б)}\ y = \frac{4}{x} + 2\]
\[\textbf{в)}\ y = \frac{4}{x + 3}\]
\[\textbf{г)}\ y = \frac{4}{x} - 2\]